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\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
International Baccalaureate · MYP 3

Algebraic Expressions and Fractions

⌚ ~106 min ▢ 11 blocks ✓ 49 exercises ➣ Prerequisites : Rational Numbers, Exponents, Algebraic Expressions
I Algebraic Expressions
I.1 Algebraic Notation
Definition — Product Notation
We can omit the \(\times\) sign when it is followed by a variable or by a bracket \((\) (also called a parenthesis).
Example
  • \(2 \times x = 2x\)
  • \(2 \times (l+w) = 2(l+w)\)
Definition — Repeated Addition
$$\overbrace{x + x + \ldots + x}^{n\text{ terms}} = n\times x$$
Definition — Repeated Multiplication
For a whole number \(n \geq 1\): $$\overbrace{x \times x \times \ldots \times x}^{n\text{ factors}} = x^n$$
Skills to practice
  • Simplifying Products of Terms with Powers
I.2 Identities and Like Terms
Definition — Identity
An identity is an equality between two expressions such that their evaluations produce the same value for all values of the variables for which both expressions are defined.
Proposition — Properties of Multiplying by 1 and 0
$$1 \times x = x \qquad \text{and} \qquad 0 \times x = 0$$
Proposition — The Commutative Laws
$$\textcolor{colordef}{a} + \textcolor{colorprop}{b} = \textcolor{colorprop}{b} + \textcolor{colordef}{a}\qquad \text{and} \qquad\textcolor{colordef}{a} \times \textcolor{colorprop}{b} = \textcolor{colorprop}{b} \times \textcolor{colordef}{a}$$
Proposition — The Associative Laws
$$(\textcolor{colordef}{a} + \textcolor{colorprop}{b}) + \textcolor{olive}{c} = \textcolor{colordef}{a} + (\textcolor{colorprop}{b} + \textcolor{olive}{c})\qquad \text{and} \qquad(\textcolor{colordef}{a} \times \textcolor{colorprop}{b}) \times \textcolor{olive}{c} = \textcolor{colordef}{a} \times (\textcolor{colorprop}{b} \times \textcolor{olive}{c})$$
Method — Simplifying by Collecting Like Terms
Simplifying an expression by collecting like terms involves combining terms that have the same variables raised to the same powers.
  1. Identify like terms: Like terms are terms that have the same variable(s) raised to the same power. For example, \(3x\) and \(5x\) are like terms, but \(3x\) and \(3x^2\) are not.
  2. Combine like terms: Add or subtract the coefficients (numerical parts) of the like terms. The variable part remains the same.
Example
Simplify the expression: \(2x + 4 + x - 2\)

$$\begin{aligned}[t]2x + 4 + x - 2 &= \textcolor{colordef}{2x} \textcolor{colorprop}{+4} \textcolor{colordef}{+x} \textcolor{colorprop}{-2} &&(\text{identifying like terms}) \\ &= \textcolor{colordef}{(2+1)x} + \textcolor{colorprop}{4-2} &&(\text{combining like terms}) \\ &= \textcolor{colordef}{3x} + \textcolor{colorprop}{2} &&(\text{simplifying})\end{aligned}$$

Proposition — Simplifying a Product
To multiply terms such as \(3x\) and \(2x\), multiply the numbers together and the letters together — the order of the factors does not matter: $$3x \times 2x = (3 \times 2) \times (x \times x) = 6x^2.$$ In particular, \(x \times x = x^2\). When simplifying a sum, like terms collect together: the \(x^2\) terms with the \(x^2\) terms, the \(x\) terms with the \(x\) terms.
Example
Simplify the products: \(5 \times 2x\);  \(3x \times 2x\);  \(x \times 4x\).

$$\begin{aligned}[t] 5 \times 2x &= (5 \times 2) \times x && {\scriptstyle\text{(group the numbers)}}\\ &= \textcolor{colordef}{10x}\\ 3x \times 2x &= (3 \times 2) \times (x \times x) && {\scriptstyle\text{(group the numbers, group the letters)}}\\ &= \textcolor{colordef}{6x^2} && {\scriptstyle(x \times x = x^2)}\\ x \times 4x &= 4 \times (x \times x) \\ &= \textcolor{colordef}{4x^2} \end{aligned}$$

Skills to practice
  • Simplifying Products of Terms
  • Simplifying Sums of Products
II Algebraic Fractions
II.1 Quotients Written as Fractions
Numerical fractions can be written, simplified, added, multiplied and divided. Their numerator and denominator are integers — numbers like \(\dfrac{2}{3}\), \(\dfrac{6}{9}\) or \(\dfrac{7}{4}\).
Algebraic fractions go one step further: the numerator or the denominator may contain a letter (for example \(x\), \(a\), \(y\)). Such a fraction is called an algebraic fraction. Every rule of numerical fractions still works. The new ideas are: how to read these expressions, when they make sense (the denominator must not take the value zero), and how to simplify them when the numerator and the denominator share a common factor.
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The fraction bar is, fundamentally, a division sign. Whenever a problem ends with divide \(A\) by \(B\), the answer can be written as the algebraic fraction \(\dfrac{A}{B}\). This is how letters naturally enter geometry, sharing problems, and any situation where the data is a quantity per unit.
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Proposition — Fraction as a Quotient
For all algebraic expressions \(A\) and \(B\) with \(B \neq 0\): $$A \div B = \dfrac{A}{B}.$$
Example
Sharing problem. You have \(x\) marbles, where \(x\) is a multiple of \(4\), and you share them equally among \(4\) friends. Each friend receives: $$x \div 4 = \dfrac{x}{4}.$$ Geometric problem. The two sides forming the right angle of a right-angled triangle both measure \(x\). Its area is half the area of a square of side \(x\): $$\text{Area} = \dfrac{x \times x}{2} = \dfrac{x^2}{2}.$$
Skills to practice
  • Writing a Quotient as a Fraction
II.2 Simplifying Algebraic Fractions
A fraction is in simplest form (or in lowest terms) when there is no common factor left between the numerator and the denominator — the common factor can be a number, a letter, or a product of both. To simplify an algebraic fraction, factorise the numerator and the denominator, then cancel every common factor. A common factor can also be a whole bracket, such as \((x-3)\).
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Method — Simplifying an algebraic fraction
  • Write the numerator and the denominator as products (factor out the numbers and the letters).
  • Identify every factor that appears both on top and on bottom.
  • Cancel each common factor (one cancellation at the top, one at the bottom, for each).
  • Multiply what remains.
The simplification is valid only for the values of the letter that do not make the original denominator zero.
Example
Simplification when only a number is shared: $$\dfrac{10x^2}{4} = \dfrac{\cancel{2}\times 5x^2}{\cancel{2}\times 2} = \dfrac{5x^2}{2}.$$ Simplification when a letter is shared too (valid for \(x \neq 0\), since the original denominator contains \(30x\)): $$\dfrac{9x^3}{30x} = \dfrac{\cancel{3}\times 3 x^2 \times \cancel{x}}{\cancel{3}\times 10 \times \cancel{x}} = \dfrac{3x^2}{10}.$$
Note
A trap to avoid: cancellation only works on factors of a product, never on terms of a sum. The fraction \(\dfrac{x+2}{2}\) cannot be simplified to \(\dfrac{x+\cancel{2}}{\cancel{2}} = x\). The \(2\) on top is a term added to \(x\), not a factor multiplying everything.
By contrast, \(\dfrac{2x+4}{2} = \dfrac{2(x+2)}{2} = x+2\) does work, because \(2\) is a common factor of both terms in the numerator \(2x+4\) and of the denominator \(2\).
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Skills to practice
  • Simplifying Algebraic Fractions
II.3 Multiplying Algebraic Fractions
Multiplying two algebraic fractions follows exactly the rule for numerical fractions: numerator times numerator, denominator times denominator. It is more efficient to simplify before multiplying whenever a factor in a numerator matches a factor in a denominator.
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Proposition — Multiplication of Algebraic Fractions
For algebraic expressions \(A\), \(B\), \(C\), \(D\) with \(B \neq 0\) and \(D \neq 0\): $$\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{A \times C}{B \times D}.$$
Example
A direct multiplication, then a simplification (valid for \(x \neq 0\)): $$ \begin{aligned} \dfrac{2x}{3} \times \dfrac{5}{4x} &= \dfrac{2x \times 5}{3 \times 4x} \\ &= \dfrac{10x}{12x} \\ &= \dfrac{\cancel{2} \times 5 \times \cancel{x}}{\cancel{2} \times 6 \times \cancel{x}} && \text{(cancel } 2,\ x\text{)} \\ &= \dfrac{5}{6}. \end{aligned} $$ Simplifying before multiplying (always faster), valid for \(x \neq 0\): $$ \begin{aligned} \dfrac{4x}{9} \times \dfrac{3}{2x} &= \dfrac{\cancel{2}\times 2 \times \cancel{x} \times \cancel{3}}{\cancel{3}\times 3 \times \cancel{2}\times \cancel{x}} && \text{(cancel } 2,\ 3,\ x\text{)} \\ &= \dfrac{2}{3}. \end{aligned} $$
Skills to practice
  • Multiplying Algebraic Fractions: Level 1
  • Multiplying Algebraic Fractions: Level 2
II.4 Dividing Algebraic Fractions
Dividing by an algebraic fraction is the same as multiplying by its reciprocal (its inverse). This is the single most useful identity to remember for algebraic fractions.
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Definition — Reciprocal of an Algebraic Fraction
The reciprocal of the fraction \(\dfrac{A}{B}\) (with \(A \neq 0\) and \(B \neq 0\)) is the fraction $$\dfrac{B}{A},$$ obtained by swapping the numerator and the denominator.
Proposition — Division of Algebraic Fractions
For algebraic expressions \(A\), \(B\), \(C\), \(D\) with \(B \neq 0\), \(C \neq 0\), \(D \neq 0\): $$\dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{A \times D}{B \times C}.$$
Example
For this division to be defined, the divisor \(\dfrac{2x}{5}\) must be non-zero, hence \(x \neq 0\): $$ \begin{aligned} \dfrac{3x}{4} \div \dfrac{2x}{5} &= \dfrac{3x}{4} \times \dfrac{5}{2x} && \text{(multiply by the reciprocal)} \\ &= \dfrac{3 \cancel{x} \times 5}{4 \times 2 \cancel{x}} && \text{(cancel } x\text{)} \\ &= \dfrac{15}{8}. \end{aligned} $$
Skills to practice
  • Dividing Algebraic Fractions
  • Simplifying Nested Fractions
III Going further
Skills to practice
  • Solving Problems in Context
  • Investigating Patterns
  • Quiz