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Calculer la valeur de l'intégrale définie \(\displaystyle \int_0^{\sqrt{\pi}} 2x\cos(x^2) \,dx\).
\(\displaystyle\int_0^{\sqrt{\pi}} 2x\cos(x^2)\;dx =\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
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6
(
)
\(\cos{\,}\)
1
2
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\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
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+
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=
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