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Soient \(A(2;\ 3)\) et \(B(7;\ -1)\).
Calcule le vecteur \(\Vect{AB}\).
\(\Vect{AB} = \begin{pmatrix} \input{126633}{}{3em}{2em}{}{} \\ \input{226633}{}{3em}{2em}{}{} \end{pmatrix}\)
7
8
9
+
4
5
6
-
1
2
3
*
C
0
,
÷
Calcule la distance \(AB\).
\(AB =\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
unités
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