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Soient \(X\) et \(Y\) deux variables aléatoires indépendantes. On sait que \(E(X)=-2\), \(V(X)=5\), \(E(Y)=6\) et \(V(Y)=4\).
On définit \(Z=5X+2Y\).
Calculer l’espérance
\(E(Z)=\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
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9
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→
\(\sin{\,}\)
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\(\cos{\,}\)
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\(\times\)
\(\div\)
\(\tan{\,}\)
C
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Calculer la variance
\(V(Z)=\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
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-
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Exit ➔