\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Show that the sequence \(u_n = \sum_{k=1}^n 1/k^2\) converges via the telescoping comparison \(1/k^2 \le 1/((k-1)k) = 1/(k-1) - 1/k\) for \(k \ge 2\).
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