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The augmented matrix \(\left( \begin{array}{cc|c} 1 & 2 & 5 \\ 0 & 1 & 2 \end{array} \right)\) is already in echelon form. Solve the corresponding \(2 \times 2\) system by back-substitution. Since the system has a unique solution, the homogeneous part is reduced to \(\{0\}\) and the solution set is the singleton \(\{X_p\}\).
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