\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Show that \(f(x) = \sqrt{x}\) is uniformly continuous on \([0, +\infty[\). Hint: use the inequality \(|\sqrt{x} - \sqrt{y}| \le \sqrt{|x - y|}\).
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