\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Show that \(f : \mathbb{R} \to \mathbb{R}\), \(f(x) = |x|\), has \(f'_g(0) = -1\) and \(f'_d(0) = 1\). Conclude that \(f\) is not differentiable at \(0\).
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