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In a gas at thermal equilibrium, the velocities of particles follow a normal distribution with a mean velocity of 500 m/s and a standard deviation of 100 m/s. A physicist wants to calculate the velocity that corresponds to one standard deviation below the mean.
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
m/s
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