\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Courses
About
Login
Register
When proving by contradiction the statement "\(\sqrt{2}\) is irrational", what is the correct initial assumption?
Assume that \(\sqrt{2}\) is a real number.
Assume that \(\sqrt{2}\) is a rational number.
Assume that \(\sqrt{2}\) is an irrational number.
Assume that \(x^2 = 2\) has no solution.
Exit