\( \definecolor{colordef}{RGB}{249,49,84} \definecolor{colorprop}{RGB}{18,102,241} \)
Prove that for all \(n \in \mathbb{Z}^+\),$$ 1^2+2^2+3^2+\dots+n^2 = \frac{n(n+1)(2n+1)}{6} $$
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