We check if this fits the form \(a^2+2ab+b^2\).
- The first term is \(x^2\), so let \(a=x\).
- The last term is \(1=1^2\), so let \(b=1\).
- We check if the middle term is \(2ab\): \(2(x)(1) = 2x\). It matches.
Therefore, the expression is a perfect square:$$\begin{aligned}x^2+2x+1 &= \textcolor{colordef}{x}^{2}+2(\textcolor{colordef}{x})(\textcolor{colorprop}{1})+\textcolor{colorprop}{1}^{2}\\
&= (\textcolor{colordef}{x}+\textcolor{colorprop}{1})^{2}.\end{aligned}$$