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C
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\(\pi\)
e
\(\frac{a}{b}\)
!
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→
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)
\(\sqrt{\,}\)
\(a^{b}\)
7
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\(\div\)
log
ln
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\(\times\)
cos
cos⁻¹
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sin
sin⁻¹
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tan
tan⁻¹
A scientist observes a culture of bacteria. Initially (at hour 0), there are \(u_0 = 50\) bacteria. Each hour, the number of bacteria doubles. Let \(u_n\) be the number of bacteria after \(n\) hours.
Part A: Write the Explicit Formula
The formula for the number of bacteria after \(n\) hours is:
\(u_n =\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
Part B: Calculate a Future Value
How many bacteria will there be after \(6\) hours?
\(u_6 = \)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
7
8
9
←
→
\(\sin{\,}\)
4
5
6
(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
C
0
.
+
-
=
bacteria
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