We divide the quadrilateral \(ABCD\) into two triangles, \(ABC\) and \(ACD\), using the diagonal \(AC\).

$$\begin{aligned}\text{Sum of the interior angles of quadrilateral } ABCD&= \text{Sum of the interior angles of } \triangle ABC \\
&\quad + \text{Sum of the interior angles of } \triangle ACD \\
&= 180^\circ + 180^\circ \\
&= 360^\circ\end{aligned}$$