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Suppose \(X\) represents the height (in centimeters) of boys in a school, and it follows a normal distribution with a mean of 175 cm and a standard deviation of 8 cm. The school states, “95\(\pourcent\) of boys can pass under a door of height 190 cm.”
Are you agree with this statement ? Explains your answer.\FieldText{1}{\(X \sim \mathcal{N}(175, 8^2)\). I calculate:$$P(X \leq 190) \approx 0.969$$I agree. It’s 96.9\(\pourcent\), close to 95\(\pourcent\).}