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The random variable \(X\) has the density \( f(x) = \frac{2}{x^2} \), on the interval \([1, 2]\). Calculate \(E(X)\).\FieldText{1}{$$\begin{aligned}[t] E(X) &= \int_{1}^{2} x \frac{2}{x^2} \, dx \\ &= \int_{1}^{2} \frac{2}{x} \, dx \\ &= 2 \left[ \ln x \right]_{1}^{2} \\ &= 2 \left( \ln 2 - \ln 1 \right) \\ &= 2 \ln 2 \end{aligned}$$}