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Let \(f(x) = x^2\) on the interval \([-2, 2]\). Does the Intermediate Value Theorem guarantee a solution for \(f(x) = -1\)?
Yes, because the function is continuous.
No, because \(-1\) is not between \(f(-2)=4\) and \(f(2)=4\).
Yes, because the function is defined at \(x=-1\).
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