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Show that \(\sin(A + B) + \sin(A - B) = 2 \sin A \cos B\).
Hence show that \(\sin A \cos B = \frac{1}{2} \sin(A + B) + \frac{1}{2} \sin(A - B)\).
Hence write the following as sums:
\(\sin 30^\circ \cos \theta\)
\(\sin 6\alpha \cos \alpha\)
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