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The lifespan of a specific battery has mean \(\mu=800\) hours and standard deviation \(\sigma=60\) hours. A technician tests a sample of \(n=100\) batteries and calculates the mean lifespan \(\overline{X}_{100}\).
Calculate the expected mean lifespan of the sample.
\(E(\overline{X}_{100})=\)
\(\pi\)
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\(x\)
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\(\frac{a}{b}\)
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\(\log{\,}\)
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\(C\)
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Calculate the standard deviation of the sample mean.
\(\sigma(\overline{X}_{100})=\)
\(\pi\)
\(e\)
\(x\)
\(n\)
\(u_n\)
\(f\)
\(i\)
\(\frac{a}{b}\)
\(\sqrt{\,}\)
\({a}^{b}\)
\(\ln{\,}\)
\(\log{\,}\)
!
\(C\)
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9
←
→
\(\sin{\,}\)
4
5
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(
)
\(\cos{\,}\)
1
2
3
\(\times\)
\(\div\)
\(\tan{\,}\)
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