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Let \(f\) be the square root function defined on \([0, +\infty)\) by \(f(x) = \sqrt{x}\).
Justify that \(f\) is strictly concave on \((0, +\infty)\).
Determine the equation of the tangent \(T\) to the graph of \(f\) at the point with abscissa \(1\).
Using the properties of concave functions, prove that for all \(x > 0\), \(\sqrt{x} \le \dfrac{1}{2}(x+1)\).
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