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Suppose \(X\) represents the noise level (in decibels) of a crowd at a school concert, and it follows a normal distribution with a mean of 85 decibels and a standard deviation of 15 decibels. The sound engineer sets a microphone threshold such that 60\(\pourcent\) of the time, the noise is below this level. Using a
normal probability calculator
Lower Limit:
Upper Limit:
Mean (μ):
Standard Deviation (σ):
Calculate
, find this noise level (i.e., the 60th percentile). Round your answer to one decimal place.
\(x \approx\)
7
8
9
+
4
5
6
-
1
2
3
*
C
0
.
÷
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