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Suppose \(X\) represents the time (in minutes) taken to complete a task, and it follows a normal distribution with a mean of 40 minutes and a standard deviation of 10 minutes. The teacher fixes the duration of the exam such that 95\(\pourcent\) of students have finished. Using a
normal probability calculator
Lower Limit:
Upper Limit:
Mean (μ):
Standard Deviation (σ):
Calculate
, find this time (i.e., the 95th percentile). Round your answer to one decimal place.
\(x \approx\)
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4
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1
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0
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