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A coach selects two players at random from a group of four players, labeled A, B, C, and D, without replacement (once a player is chosen, they are not available for the next selection). The table below shows all possible outcomes for selecting Player 1 and Player 2, where an "X" indicates an impossible outcome due to the same player being selected twice.
Player 2
Player 1
A
B
C
D
A
X
A
B
A
C
A
D
B
B
A
X
B
C
B
D
C
C
A
C
B
X
C
D
D
D
A
D
B
D
C
X
Calculate the probability that player C is selected as either Player 1 or Player 2, simplifying the fraction.
P
(
"selecting player C"
)
=
7
8
9
4
5
6
1
2
3
C
0
,
7
8
9
4
5
6
1
2
3
C
0
,
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