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\(\dollar 1000\) is placed in an account that earns \(10 \pourcent\) interest per annum (p.a.), and the interest is allowed to compound over three years. This means the account is earning \(10 \pourcent\) p.a. in compound interest.
Fill the compound interest table (
calculatrice
!
e
\(\pi\)
(
)
%
AC
sin
cos
tan
7
8
9
/
\(\sin^{-1}\)
\(\cos^{-1}\)
\(\tan^{-1}\)
4
5
6
*
\(x^2\)
\(\sqrt{\phantom{2}}\)
x
y
1
2
3
-
ln
exp
log
0
.
=
+
).
Year
Amount
Compound interest
0
\(\dollar 1000\)
\(10 \pourcent\) of \(\dollar 1000=\dollar 100\)
1
\(\dollar 1000+\dollar 100=\dollar 1100\)
\(10 \pourcent\) of \(\dollar 1100=\dollar 110\)
2
\(\dollar\)
7
8
9
4
5
6
1
2
3
C
0
.
7
8
9
4
5
6
1
2
3
C
0
.
3
\(\dollar\)
7
8
9
4
5
6
1
2
3
C
0
.
Find the amount at 3 years.
7
8
9
4
5
6
1
2
3
C
0
.
dollars
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